Distance from Bexley to Aleksandrow Lodzki
The shortest distance (air line) between Bexley and Aleksandrow Lodzki is 4,569.94 mi (7,354.61 km).
How far is Bexley from Aleksandrow Lodzki
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 20:29 (14.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:29 (15.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,569.94 miles which is equal to 7,354.61 km.
Related Distances from Bexley
Aleksandrow Lodzki, Łódzki, Poland