Distance from Bexley to Bolintin Vale
The shortest distance (air line) between Bexley and Bolintin Vale is 5,117.85 mi (8,236.38 km).
How far is Bexley from Bolintin Vale
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 15:23 (11.02.2025)
Bolintin Vale is located in Giurgiu, Romania within 44° 26' 49.92" N 25° 45' 25.92" E (44.4472, 25.7572) coordinates. The local time in Bolintin Vale is 22:23 (11.02.2025)
The calculated flying distance from Bolintin Vale to Bolintin Vale is 5,117.85 miles which is equal to 8,236.38 km.
Related Distances from Bexley
Bolintin Vale, Giurgiu, Romania