Distance from Bexley to Jefferson Valley-Yorktown
The shortest distance (air line) between Bexley and Jefferson Valley-Yorktown is 487.64 mi (784.79 km).
How far is Bexley from Jefferson Valley-Yorktown
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 02:16 (12.03.2025)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 02:16 (12.03.2025)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 487.64 miles which is equal to 784.79 km.
Related Distances from Bexley
Jefferson Valley-Yorktown, New York, United States