Distance from Bexley to Lappersdorf
The shortest distance (air line) between Bexley and Lappersdorf is 4,409.69 mi (7,096.71 km).
How far is Bexley from Lappersdorf
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 22:12 (10.01.2025)
Lappersdorf is located in Regensburg; Landkreis, Germany within 49° 3' 9" N 12° 5' 25.08" E (49.0525, 12.0903) coordinates. The local time in Lappersdorf is 04:12 (11.01.2025)
The calculated flying distance from Lappersdorf to Lappersdorf is 4,409.69 miles which is equal to 7,096.71 km.
Related Distances from Bexley
Lappersdorf, Regensburg; Landkreis, Germany