Distance from Bexley to Levallois-Perret
The shortest distance (air line) between Bexley and Levallois-Perret is 4,025.83 mi (6,478.95 km).
How far is Bexley from Levallois-Perret
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 23:47 (01.12.2024)
Levallois-Perret is located in Hauts-de-Seine, France within 48° 53' 42" N 2° 17' 13.92" E (48.8950, 2.2872) coordinates. The local time in Levallois-Perret is 05:47 (02.12.2024)
The calculated flying distance from Levallois-Perret to Levallois-Perret is 4,025.83 miles which is equal to 6,478.95 km.
Related Distances from Bexley
Levallois-Perret, Hauts-de-Seine, France