Distance from Bexley to Mercato San Severino
The shortest distance (air line) between Bexley and Mercato San Severino is 4,837.47 mi (7,785.16 km).
How far is Bexley from Mercato San Severino
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 12:08 (16.01.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 18:08 (16.01.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 4,837.47 miles which is equal to 7,785.16 km.
Related Distances from Bexley
Mercato San Severino, Salerno, Italy