Distance from Bexley to San Cesareo
The shortest distance (air line) between Bexley and San Cesareo is 4,712.91 mi (7,584.69 km).
How far is Bexley from San Cesareo
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 18:43 (17.01.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 00:43 (18.01.2025)
The calculated flying distance from San Cesareo to San Cesareo is 4,712.91 miles which is equal to 7,584.69 km.