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      Distance from Bexley to San Ferdinando di Puglia

      The shortest distance (air line) between Bexley and San Ferdinando di Puglia is 4,870.91 mi (7,838.97 km).

      How far is Bexley from San Ferdinando di Puglia

      Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 19:38 (17.01.2025)

      San Ferdinando di Puglia is located in Barletta-Andria-Trani, Italy within 41° 17' 60" N 16° 4' 0.12" E (41.3000, 16.0667) coordinates. The local time in San Ferdinando di Puglia is 01:38 (18.01.2025)

      The calculated flying distance from San Ferdinando di Puglia to San Ferdinando di Puglia is 4,870.91 miles which is equal to 7,838.97 km.

      Bexley, Ohio, United States

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      San Ferdinando di Puglia, Barletta-Andria-Trani, Italy

      Related Distances to San Ferdinando di Puglia