Distance from Bexley to San Juan del Puerto
The shortest distance (air line) between Bexley and San Juan del Puerto is 3,979.87 mi (6,404.98 km).
How far is Bexley from San Juan del Puerto
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 06:01 (23.02.2025)
San Juan del Puerto is located in Huelva, Spain within 37° 19' 0.12" N -7° 10' 0.12" W (37.3167, -6.8333) coordinates. The local time in San Juan del Puerto is 12:01 (23.02.2025)
The calculated flying distance from San Juan del Puerto to San Juan del Puerto is 3,979.87 miles which is equal to 6,404.98 km.
Related Distances from Bexley
San Juan del Puerto, Huelva, Spain