Distance from Bexley to San Lazzaro di Savena
The shortest distance (air line) between Bexley and San Lazzaro di Savena is 4,552.08 mi (7,325.87 km).
How far is Bexley from San Lazzaro di Savena
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 07:49 (30.01.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 13:49 (30.01.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,552.08 miles which is equal to 7,325.87 km.
Related Distances from Bexley
San Lazzaro di Savena, Bologna, Italy