Distance from Bexley to San Martino Buon Albergo
The shortest distance (air line) between Bexley and San Martino Buon Albergo is 4,504.11 mi (7,248.66 km).
How far is Bexley from San Martino Buon Albergo
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 07:49 (30.01.2025)
San Martino Buon Albergo is located in Verona, Italy within 45° 25' 0.12" N 11° 5' 60" E (45.4167, 11.1000) coordinates. The local time in San Martino Buon Albergo is 13:49 (30.01.2025)
The calculated flying distance from San Martino Buon Albergo to San Martino Buon Albergo is 4,504.11 miles which is equal to 7,248.66 km.
Related Distances from Bexley
San Martino Buon Albergo, Verona, Italy