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      Distance from Bexley to San Pancrazio Salentino

      The shortest distance (air line) between Bexley and San Pancrazio Salentino is 4,981.34 mi (8,016.70 km).

      How far is Bexley from San Pancrazio Salentino

      Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 21:06 (17.01.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 03:06 (18.01.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 4,981.34 miles which is equal to 8,016.70 km.

      Bexley, Ohio, United States

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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino