Distance from Bexley to San Severino Marche
The shortest distance (air line) between Bexley and San Severino Marche is 4,673.23 mi (7,520.84 km).
How far is Bexley from San Severino Marche
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 21:10 (17.01.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 03:10 (18.01.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,673.23 miles which is equal to 7,520.84 km.
Related Distances from Bexley
San Severino Marche, Macerata, Italy