Distance from Bexley to San Vito dei Normanni
The shortest distance (air line) between Bexley and San Vito dei Normanni is 4,965.87 mi (7,991.80 km).
How far is Bexley from San Vito dei Normanni
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 08:06 (30.01.2025)
San Vito dei Normanni is located in Brindisi, Italy within 40° 39' 20.16" N 17° 42' 12.96" E (40.6556, 17.7036) coordinates. The local time in San Vito dei Normanni is 14:06 (30.01.2025)
The calculated flying distance from San Vito dei Normanni to San Vito dei Normanni is 4,965.87 miles which is equal to 7,991.80 km.
Related Distances from Bexley
San Vito dei Normanni, Brindisi, Italy