Distance from Bexley to Sansepolcro
The shortest distance (air line) between Bexley and Sansepolcro is 4,616.87 mi (7,430.13 km).
How far is Bexley from Sansepolcro
Bexley is located in Ohio, United States within 39° 57' 54" N -83° 3' 56.52" W (39.9650, -82.9343) coordinates. The local time in Bexley is 07:55 (30.01.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 13:55 (30.01.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,616.87 miles which is equal to 7,430.13 km.