Distance from Bloomington to Asenovgrad
The shortest distance (air line) between Bloomington and Asenovgrad is 5,396.63 mi (8,685.04 km).
How far is Bloomington from Asenovgrad
Bloomington is located in Illinois, United States within 40° 28' 32.52" N -89° 1' 46.92" W (40.4757, -88.9703) coordinates. The local time in Bloomington is 08:41 (27.11.2024)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 16:41 (27.11.2024)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,396.63 miles which is equal to 8,685.04 km.
Bloomington, Illinois, United States