Distance from Bloomsburg to Begijnendijk
The shortest distance (air line) between Bloomsburg and Begijnendijk is 3,757.78 mi (6,047.56 km).
How far is Bloomsburg from Begijnendijk
Bloomsburg is located in Pennsylvania, United States within 41° 0' 9.72" N -77° 32' 38.04" W (41.0027, -76.4561) coordinates. The local time in Bloomsburg is 01:48 (15.11.2024)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 07:48 (15.11.2024)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,757.78 miles which is equal to 6,047.56 km.
Bloomsburg, Pennsylvania, United States
Related Distances from Bloomsburg
Begijnendijk, Arr. Leuven, Belgium