Distance from Bloomsburg to Steenokkerzeel
The shortest distance (air line) between Bloomsburg and Steenokkerzeel is 3,749.46 mi (6,034.17 km).
How far is Bloomsburg from Steenokkerzeel
Bloomsburg is located in Pennsylvania, United States within 41° 0' 9.72" N -77° 32' 38.04" W (41.0027, -76.4561) coordinates. The local time in Bloomsburg is 13:46 (15.11.2024)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 19:46 (15.11.2024)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,749.46 miles which is equal to 6,034.17 km.
Bloomsburg, Pennsylvania, United States
Related Distances from Bloomsburg
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium