Distance from Bloomsburg to Sveti Ivan Zelina
The shortest distance (air line) between Bloomsburg and Sveti Ivan Zelina is 4,384.20 mi (7,055.68 km).
How far is Bloomsburg from Sveti Ivan Zelina
Bloomsburg is located in Pennsylvania, United States within 41° 0' 9.72" N -77° 32' 38.04" W (41.0027, -76.4561) coordinates. The local time in Bloomsburg is 19:30 (15.11.2024)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 01:30 (16.11.2024)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,384.20 miles which is equal to 7,055.68 km.
Bloomsburg, Pennsylvania, United States
Related Distances from Bloomsburg
Sveti Ivan Zelina, Zagrebačka županija, Croatia