Distance from Blunsdon Saint Andrew to Gainesville
The shortest distance (air line) between Blunsdon Saint Andrew and Gainesville is 4,251.58 mi (6,842.26 km).
How far is Blunsdon Saint Andrew from Gainesville
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 05:51 (18.12.2025)
Gainesville is located in Florida, United States within 29° 40' 49.44" N -83° 39' 14.76" W (29.6804, -82.3459) coordinates. The local time in Gainesville is 00:51 (18.12.2025)
The calculated flying distance from Gainesville to Gainesville is 4,251.58 miles which is equal to 6,842.26 km.
Blunsdon Saint Andrew, Swindon, United Kingdom
Related Distances from Blunsdon Saint Andrew
Gainesville, Florida, United States