Distance from Blunsdon Saint Andrew to Harker Heights
The shortest distance (air line) between Blunsdon Saint Andrew and Harker Heights is 4,802.47 mi (7,728.83 km).
How far is Blunsdon Saint Andrew from Harker Heights
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 21:14 (17.12.2025)
Harker Heights is located in Texas, United States within 31° 3' 25.92" N -98° 21' 19.44" W (31.0572, -97.6446) coordinates. The local time in Harker Heights is 15:14 (17.12.2025)
The calculated flying distance from Harker Heights to Harker Heights is 4,802.47 miles which is equal to 7,728.83 km.
Blunsdon Saint Andrew, Swindon, United Kingdom
Related Distances from Blunsdon Saint Andrew
Harker Heights, Texas, United States