Distance from Blunsdon Saint Andrew to Jefferson Hills
The shortest distance (air line) between Blunsdon Saint Andrew and Jefferson Hills is 3,650.08 mi (5,874.24 km).
How far is Blunsdon Saint Andrew from Jefferson Hills
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 00:26 (18.12.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 19:26 (17.12.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 3,650.08 miles which is equal to 5,874.24 km.
Blunsdon Saint Andrew, Swindon, United Kingdom
Related Distances from Blunsdon Saint Andrew
Jefferson Hills, Pennsylvania, United States