Distance from Blunsdon Saint Andrew to Lake Stevens
The shortest distance (air line) between Blunsdon Saint Andrew and Lake Stevens is 4,705.94 mi (7,573.48 km).
How far is Blunsdon Saint Andrew from Lake Stevens
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 20:00 (18.12.2025)
Lake Stevens is located in Washington, United States within 48° 0' 8.64" N -123° 54' 16.92" W (48.0024, -122.0953) coordinates. The local time in Lake Stevens is 12:00 (18.12.2025)
The calculated flying distance from Lake Stevens to Lake Stevens is 4,705.94 miles which is equal to 7,573.48 km.
Blunsdon Saint Andrew, Swindon, United Kingdom
Related Distances from Blunsdon Saint Andrew
Lake Stevens, Washington, United States