Distance from Blunsdon Saint Andrew to Peekskill
The shortest distance (air line) between Blunsdon Saint Andrew and Peekskill is 3,362.96 mi (5,412.17 km).
How far is Blunsdon Saint Andrew from Peekskill
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 09:56 (03.01.2026)
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 04:56 (03.01.2026)
The calculated flying distance from Peekskill to Peekskill is 3,362.96 miles which is equal to 5,412.17 km.
Blunsdon Saint Andrew, Swindon, United Kingdom
Related Distances from Blunsdon Saint Andrew
Peekskill, New York, United States