Distance from Blunsdon Saint Andrew to Petersburg
The shortest distance (air line) between Blunsdon Saint Andrew and Petersburg is 3,686.10 mi (5,932.21 km).
How far is Blunsdon Saint Andrew from Petersburg
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 19:09 (22.12.2025)
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 14:09 (22.12.2025)
The calculated flying distance from Petersburg to Petersburg is 3,686.10 miles which is equal to 5,932.21 km.
Blunsdon Saint Andrew, Swindon, United Kingdom
Related Distances from Blunsdon Saint Andrew
Petersburg, Virginia, United States