Distance from Boguszow-Gorce to Jacksonville
The shortest distance (air line) between Boguszow-Gorce and Jacksonville is 4,944.04 mi (7,956.67 km).
How far is Boguszow-Gorce from Jacksonville
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 21:32 (06.12.2025)
Jacksonville is located in Florida, United States within 30° 19' 55.92" N -82° 19' 30.36" W (30.3322, -81.6749) coordinates. The local time in Jacksonville is 15:32 (06.12.2025)
The calculated flying distance from Jacksonville to Jacksonville is 4,944.04 miles which is equal to 7,956.67 km.
Boguszow-Gorce, Wałbrzyski, Poland
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Jacksonville, Florida, United States