Distance from Boguszow-Gorce to Sacramento
The shortest distance (air line) between Boguszow-Gorce and Sacramento is 5,752.87 mi (9,258.35 km).
How far is Boguszow-Gorce from Sacramento
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 17:53 (03.01.2026)
Sacramento is located in California, United States within 38° 34' 3.72" N -122° 31' 53.4" W (38.5677, -121.4685) coordinates. The local time in Sacramento is 08:53 (03.01.2026)
The calculated flying distance from Sacramento to Sacramento is 5,752.87 miles which is equal to 9,258.35 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Sacramento, California, United States