Distance from Boguszow-Gorce to San Angelo
The shortest distance (air line) between Boguszow-Gorce and San Angelo is 5,574.19 mi (8,970.80 km).
How far is Boguszow-Gorce from San Angelo
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 05:39 (19.12.2025)
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 22:39 (18.12.2025)
The calculated flying distance from San Angelo to San Angelo is 5,574.19 miles which is equal to 8,970.80 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
San Angelo, Texas, United States