Distance from Boguszow-Gorce to San Leandro
The shortest distance (air line) between Boguszow-Gorce and San Leandro is 5,822.65 mi (9,370.65 km).
How far is Boguszow-Gorce from San Leandro
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 07:46 (19.12.2025)
San Leandro is located in California, United States within 37° 42' 26.64" N -123° 50' 24.36" W (37.7074, -122.1599) coordinates. The local time in San Leandro is 22:46 (18.12.2025)
The calculated flying distance from San Leandro to San Leandro is 5,822.65 miles which is equal to 9,370.65 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
San Leandro, California, United States