Distance from Boguszow-Gorce to Savage
The shortest distance (air line) between Boguszow-Gorce and Savage is 4,611.03 mi (7,420.74 km).
How far is Boguszow-Gorce from Savage
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 12:39 (13.01.2026)
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 05:39 (13.01.2026)
The calculated flying distance from Savage to Savage is 4,611.03 miles which is equal to 7,420.74 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Savage, Minnesota, United States