Distance from Boguszow-Gorce to Sayville
The shortest distance (air line) between Boguszow-Gorce and Sayville is 4,092.47 mi (6,586.19 km).
How far is Boguszow-Gorce from Sayville
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 22:01 (05.01.2026)
Sayville is located in New York, United States within 40° 44' 52.08" N -74° 54' 57.6" W (40.7478, -73.0840) coordinates. The local time in Sayville is 16:01 (05.01.2026)
The calculated flying distance from Sayville to Sayville is 4,092.47 miles which is equal to 6,586.19 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Sayville, New York, United States