Distance from Boguszow-Gorce to Seven Hills
The shortest distance (air line) between Boguszow-Gorce and Seven Hills is 4,383.76 mi (7,054.98 km).
How far is Boguszow-Gorce from Seven Hills
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 03:31 (14.01.2026)
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 21:31 (13.01.2026)
The calculated flying distance from Seven Hills to Seven Hills is 4,383.76 miles which is equal to 7,054.98 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Seven Hills, Ohio, United States