Distance from Boguszow-Gorce to Seymour
The shortest distance (air line) between Boguszow-Gorce and Seymour is 4,658.71 mi (7,497.46 km).
How far is Boguszow-Gorce from Seymour
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 17:23 (04.01.2026)
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 11:23 (04.01.2026)
The calculated flying distance from Seymour to Seymour is 4,658.71 miles which is equal to 7,497.46 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Seymour, Indiana, United States