Distance from Boguszow-Gorce to Shenandoah
The shortest distance (air line) between Boguszow-Gorce and Shenandoah is 5,297.00 mi (8,524.70 km).
How far is Boguszow-Gorce from Shenandoah
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 17:09 (19.12.2025)
Shenandoah is located in Louisiana, United States within 30° 24' 6.84" N -92° 59' 52.8" W (30.4019, -91.0020) coordinates. The local time in Shenandoah is 10:09 (19.12.2025)
The calculated flying distance from Shenandoah to Shenandoah is 5,297.00 miles which is equal to 8,524.70 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Shenandoah, Louisiana, United States