Distance from Boguszow-Gorce to Sicklerville
The shortest distance (air line) between Boguszow-Gorce and Sicklerville is 4,213.30 mi (6,780.66 km).
How far is Boguszow-Gorce from Sicklerville
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 21:22 (19.12.2025)
Sicklerville is located in New Jersey, United States within 39° 44' 42.72" N -75° 0' 23.76" W (39.7452, -74.9934) coordinates. The local time in Sicklerville is 15:22 (19.12.2025)
The calculated flying distance from Sicklerville to Sicklerville is 4,213.30 miles which is equal to 6,780.66 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Sicklerville, New Jersey, United States