Distance from Boguszow-Gorce to Susanville
The shortest distance (air line) between Boguszow-Gorce and Susanville is 5,617.73 mi (9,040.87 km).
How far is Boguszow-Gorce from Susanville
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 19:44 (13.01.2026)
Susanville is located in California, United States within 40° 25' 14.16" N -121° 23' 12.48" W (40.4206, -120.6132) coordinates. The local time in Susanville is 10:44 (13.01.2026)
The calculated flying distance from Susanville to Susanville is 5,617.73 miles which is equal to 9,040.87 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Susanville, California, United States