Distance from Boguszow-Gorce to Titusville
The shortest distance (air line) between Boguszow-Gorce and Titusville is 5,001.48 mi (8,049.10 km).
How far is Boguszow-Gorce from Titusville
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 06:13 (14.01.2026)
Titusville is located in Florida, United States within 28° 34' 21.72" N -81° 10' 50.52" W (28.5727, -80.8193) coordinates. The local time in Titusville is 00:13 (14.01.2026)
The calculated flying distance from Titusville to Titusville is 5,001.48 miles which is equal to 8,049.10 km.
Boguszow-Gorce, Wałbrzyski, Poland
Related Distances from Boguszow-Gorce
Titusville, Florida, United States