Distance from Bolintin Vale to Cesky Tesin
The shortest distance (air line) between Bolintin Vale and Cesky Tesin is 496.10 mi (798.39 km).
How far is Bolintin Vale from Cesky Tesin
Bolintin Vale is located in Giurgiu, Romania within 44° 26' 49.92" N 25° 45' 25.92" E (44.4472, 25.7572) coordinates. The local time in Bolintin Vale is 08:57 (26.02.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 07:57 (26.02.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 496.10 miles which is equal to 798.39 km.
Bolintin Vale, Giurgiu, Romania
Related Distances from Bolintin Vale
Cesky Tesin, Moravskoslezský kraj, Czechia