Distance from Boortmeerbeek to Cesky Tesin
The shortest distance (air line) between Boortmeerbeek and Cesky Tesin is 624.55 mi (1,005.12 km).
How far is Boortmeerbeek from Cesky Tesin
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 07:30 (24.11.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 07:30 (24.11.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 624.55 miles which is equal to 1,005.12 km.
Boortmeerbeek, Arr. Leuven, Belgium
Related Distances from Boortmeerbeek
Cesky Tesin, Moravskoslezský kraj, Czechia