Distance from Bothell to San Angelo
The shortest distance (air line) between Bothell and San Angelo is 1,606.14 mi (2,584.84 km).
How far is Bothell from San Angelo
Bothell is located in Washington, United States within 47° 46' 24.6" N -123° 47' 44.16" W (47.7735, -122.2044) coordinates. The local time in Bothell is 05:34 (16.01.2026)
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 07:34 (16.01.2026)
The calculated flying distance from San Angelo to San Angelo is 1,606.14 miles which is equal to 2,584.84 km.
Bothell, Washington, United States
Related Distances from Bothell
San Angelo, Texas, United States