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      Distance from Bothell to San Juan de Aznalfarache

      The shortest distance (air line) between Bothell and San Juan de Aznalfarache is 5,365.85 mi (8,635.51 km).

      How far is Bothell from San Juan de Aznalfarache

      Bothell is located in Washington, United States within 47° 46' 24.6" N -123° 47' 44.16" W (47.7735, -122.2044) coordinates. The local time in Bothell is 17:43 (21.05.2025)

      San Juan de Aznalfarache is located in Sevilla, Spain within 37° 22' 0.12" N -7° 58' 59.88" W (37.3667, -6.0167) coordinates. The local time in San Juan de Aznalfarache is 02:43 (22.05.2025)

      The calculated flying distance from San Juan de Aznalfarache to San Juan de Aznalfarache is 5,365.85 miles which is equal to 8,635.51 km.

      Bothell, Washington, United States

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      San Juan de Aznalfarache, Sevilla, Spain

      Related Distances to San Juan de Aznalfarache