Distance from Boynton Beach to Dimitrovgrad
The shortest distance (air line) between Boynton Beach and Dimitrovgrad is 5,586.06 mi (8,989.90 km).
How far is Boynton Beach from Dimitrovgrad
Boynton Beach is located in Florida, United States within 26° 31' 41.16" N -81° 55' 8.04" W (26.5281, -80.0811) coordinates. The local time in Boynton Beach is 15:38 (16.04.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 21:38 (16.04.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,586.06 miles which is equal to 8,989.90 km.
Boynton Beach, Florida, United States
Related Distances from Boynton Beach
Dimitrovgrad, Pirotska oblast, Serbia