Distance from Boynton Beach to Levallois-Perret
The shortest distance (air line) between Boynton Beach and Levallois-Perret is 4,525.75 mi (7,283.49 km).
How far is Boynton Beach from Levallois-Perret
Boynton Beach is located in Florida, United States within 26° 31' 41.16" N -81° 55' 8.04" W (26.5281, -80.0811) coordinates. The local time in Boynton Beach is 07:20 (29.12.2025)
Levallois-Perret is located in Hauts-de-Seine, France within 48° 53' 42" N 2° 17' 13.92" E (48.8950, 2.2872) coordinates. The local time in Levallois-Perret is 13:20 (29.12.2025)
The calculated flying distance from Levallois-Perret to Levallois-Perret is 4,525.75 miles which is equal to 7,283.49 km.
Boynton Beach, Florida, United States
Related Distances from Boynton Beach
Levallois-Perret, Hauts-de-Seine, France