Distance from Boynton Beach to Scherpenheuvel
The shortest distance (air line) between Boynton Beach and Scherpenheuvel is 4,607.91 mi (7,415.71 km).
How far is Boynton Beach from Scherpenheuvel
Boynton Beach is located in Florida, United States within 26° 31' 41.16" N -81° 55' 8.04" W (26.5281, -80.0811) coordinates. The local time in Boynton Beach is 16:30 (07.04.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 22:30 (07.04.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 4,607.91 miles which is equal to 7,415.71 km.
Boynton Beach, Florida, United States
Related Distances from Boynton Beach
Scherpenheuvel, Arr. Leuven, Belgium