Distance from Brooklyn Park to Sveti Ivan Zelina
The shortest distance (air line) between Brooklyn Park and Sveti Ivan Zelina is 4,824.95 mi (7,765.01 km).
How far is Brooklyn Park from Sveti Ivan Zelina
Brooklyn Park is located in Minnesota, United States within 45° 6' 40.32" N -94° 38' 58.2" W (45.1112, -93.3505) coordinates. The local time in Brooklyn Park is 02:33 (20.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 09:33 (20.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,824.95 miles which is equal to 7,765.01 km.
Brooklyn Park, Minnesota, United States
Related Distances from Brooklyn Park
Sveti Ivan Zelina, Zagrebačka županija, Croatia