Distance from Brownsville to Scherpenheuvel
The shortest distance (air line) between Brownsville and Scherpenheuvel is 5,344.49 mi (8,601.13 km).
How far is Brownsville from Scherpenheuvel
Brownsville is located in Texas, United States within 25° 59' 51" N -98° 32' 31.2" W (25.9975, -97.4580) coordinates. The local time in Brownsville is 10:26 (07.04.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 17:26 (07.04.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 5,344.49 miles which is equal to 8,601.13 km.
Brownsville, Texas, United States
Related Distances from Brownsville
Scherpenheuvel, Arr. Leuven, Belgium