Distance from Burnsville to Sveti Ivan Zelina
The shortest distance (air line) between Burnsville and Sveti Ivan Zelina is 4,839.67 mi (7,788.70 km).
How far is Burnsville from Sveti Ivan Zelina
Burnsville is located in Minnesota, United States within 44° 45' 53.28" N -94° 43' 14.52" W (44.7648, -93.2793) coordinates. The local time in Burnsville is 11:52 (15.11.2024)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 18:52 (15.11.2024)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,839.67 miles which is equal to 7,788.70 km.
Burnsville, Minnesota, United States
Related Distances from Burnsville
Sveti Ivan Zelina, Zagrebačka županija, Croatia