Distance from Cedar Falls to Sankt Polten
The shortest distance (air line) between Cedar Falls and Sankt Polten is 4,796.77 mi (7,719.66 km).
How far is Cedar Falls from Sankt Polten
Cedar Falls is located in Iowa, United States within 42° 31' 10.2" N -93° 32' 47.04" W (42.5195, -92.4536) coordinates. The local time in Cedar Falls is 05:22 (30.11.2024)
Sankt Polten is located in Sankt Pölten, Austria within 48° 12' 0" N 15° 37' 0.12" E (48.2000, 15.6167) coordinates. The local time in Sankt Polten is 12:22 (30.11.2024)
The calculated flying distance from Sankt Polten to Sankt Polten is 4,796.77 miles which is equal to 7,719.66 km.
Cedar Falls, Iowa, United States
Related Distances from Cedar Falls
Sankt Polten, Sankt Pölten, Austria