Distance from Celakovice to Blunsdon Saint Andrew
The shortest distance (air line) between Celakovice and Blunsdon Saint Andrew is 726.29 mi (1,168.84 km).
How far is Celakovice from Blunsdon Saint Andrew
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 11:53 (08.06.2025)
Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 10:53 (08.06.2025)
The calculated flying distance from Blunsdon Saint Andrew to Blunsdon Saint Andrew is 726.29 miles which is equal to 1,168.84 km.
Celakovice, Středočeský kraj, Czechia
Related Distances from Celakovice
Blunsdon Saint Andrew, Swindon, United Kingdom