Distance from Celakovice to Sint Anthonis
The shortest distance (air line) between Celakovice and Sint Anthonis is 399.28 mi (642.58 km).
How far is Celakovice from Sint Anthonis
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 15:07 (16.05.2025)
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 15:07 (16.05.2025)
The calculated flying distance from Sint Anthonis to Sint Anthonis is 399.28 miles which is equal to 642.58 km.
Celakovice, Středočeský kraj, Czechia
Related Distances from Celakovice
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands